a, 2Fe+3Cl₂ -> 2FeCl₃

b, K + H₂O -> KOH + \(\dfrac{1}{2}\)H₂

c, Al+3HCl -> AlCl₃ + \(\dfrac{3}{2}\)H2

d, CH₄ + 2O₂ -> CO₂ + 2H₂O

a, 2Cu + O₂ -> 2CuO

b, MnO₂ + 4HCl -> MnCl₂ + Cl₂ + 2H₂O

\(C_6^3+C_6^2.C_4^1+C_6^1.C_4^2=116\left(cách\right)\)

Làm thoyy

:)

 \(R_{tđ}=R_1+R_2=600+400=1000\left(\Omega\right)\)

\(I=\dfrac{U}{R_{tđ}}=\dfrac{220}{1000}\left(A\right)=I_1=I_2\)

\(U_1=I_1.R_1=\dfrac{220}{1000}.600=132\left(V\right)\)

\(U_2=I_2.R_2=\dfrac{220}{1000}.400=88\left(V\right)\)

a, \(R_{12}=\dfrac{R_1.R_2}{R_1+R_2}=6\left(\Omega\right)\)

\(R_{tđ}=R_{12}+R_3=6+20=26\left(\Omega\right)\)

b, \(I_{AB}=\dfrac{U_{AB}}{R_{AB}}=\dfrac{45}{26}\left(A\right)=I_{12}=I_3\)

\(U_{12}=I_{12}.R_{12}=\dfrac{45}{26}.6=\dfrac{135}{13}\left(V\right)=U_1=U_2\)

\(I_1=\dfrac{U_1}{R_1}=\dfrac{\dfrac{135}{13}}{10}=\dfrac{27}{26}\left(A\right)\)

\(I_2=\dfrac{U_2}{I_2}=\dfrac{\dfrac{135}{13}}{15}=\dfrac{9}{13}\left(A\right)\)

Tưởng I3 = U3/R3 mà

Tưởng I3 = U3/R3 mà