a,

\(W_t=m\cdot g\cdot z=2\cdot10\cdot100=2000J\)

b,

Áp dụng ĐLBTCN :

\(W=W_1\\ \Leftrightarrow\dfrac{1}{2}\cdot m\cdot V^2+m\cdot g\cdot z=\dfrac{1}{2}\cdot m\cdot V_1+m\cdot g\cdot z_1^2\\ \Leftrightarrow m\cdot g\cdot z=\dfrac{1}{2}\cdot m\cdot V_1^2\\ \Leftrightarrow2000=\dfrac{1}{2}\cdot2\cdot V_1^2\\ \Leftrightarrow V_1=20\sqrt{5}\)

c,

Ta có:

\(W_{t_{30}}=m\cdot g\cdot30=2\cdot10\cdot30=600J\)

\(V_{30}=\sqrt{2\cdot g\cdot S}=\sqrt{2\cdot10\cdot70}=10\sqrt{14}\) m/s

\(W_{đ_{30}}=\dfrac{1}{2}\cdot2\cdot V_{30}^2=\dfrac{1}{2}\cdot2\cdot\left(10\sqrt{14}\right)^2=1400J\)

1+1=2

3+9=12

Đề có bị lỗi không bạn ?

\(\dfrac{28}{15}\cdot\dfrac{1}{4^2}\cdot3+\left(\dfrac{8}{15}-\dfrac{69}{60}\cdot\dfrac{5}{23}\right):\dfrac{51}{54}\\ =\dfrac{7}{5}\cdot\dfrac{1}{4}+\left(\dfrac{8}{15}-\dfrac{3}{6}\right)\cdot\dfrac{54}{51}\\ =\dfrac{7}{20}+\dfrac{1}{30}\cdot\dfrac{54}{51}\\ =\dfrac{7}{20}+\dfrac{3}{85}\\ =\dfrac{131}{340}\)

a. 

\(\dfrac{6}{9}=\dfrac{2}{3};\dfrac{6}{24}=\dfrac{1}{4};\dfrac{48}{96}=\dfrac{1}{2};\dfrac{42}{98}=\dfrac{3}{7}\) 

b.

\(\dfrac{24}{36}=\dfrac{2}{3};\dfrac{18}{30}=\dfrac{3}{5};\dfrac{15}{120}=\dfrac{1}{8};\dfrac{80}{240}=\dfrac{1}{2}\)

à ý mình là câu trả lời trên chỉ man tính chất tham khảo thôi chứ k nhất thiết là theo lớp 6