mik cx như bn Tạ Tuấn Anh thôi
2
10
A
A
D
cho hỏi bài này đâu phải bài lớp 1 đâu![]()
A
a, A=√x+2√x=√16+2√16=4+24=64=32A=x+2x=16+216=4+24=64=32
b, B=xx−4+1√x−2+1√x+2B=xx−4+1x−2+1x+2
⇒B=x(√x−2)(√x+2)+√x+2(√x−2)(√x+2)+√x−2(√x−2)(√x+2)⇒B=x(x−2)(x+2)+x+2(x−2)(x+2)+x−2(x−2)(x+2)
⇒B=x+√x+2+√x−2(√x−2)(√x+2)⇒B=x+x+2+x−2(x−2)(x+2)
⇒B=x+2√x(√x−2)(√x+2)⇒B=x+2x(x−2)(x+2)
⇒B=√x(√x+2)(√x−2)(√x+2)⇒B=x(x+2)(x−2)(x+2)
⇒B=√x√x−2⇒B=xx−2
c,AB=√x+2√x.√x√x−2AB=x+2x.xx−2
⇒AB=√x+2√x−2⇒AB=x+2x−2
⇒AB=√x−2+4√x−2⇒AB=x−2+4x−2
⇒AB=1+4√x−2⇒AB=1+4x−2
Để AB nguyên thì 4√x−2∈Z⇒√x−2∈Ư(4)4x−2∈Z⇒x−2∈Ư(4)
Ta có bảng:
| √x−2x−2 | -4 | -2 | -1 | 1 | 2 | 4 |
| x | vô lí | 0 (ktm) | 1 | 9 | 16 | 36 |
Vậy x∈{1;9;16;36}