MTC= \(12x^3y^4z^2\)

Ta có: \(\dfrac{5}{3x^2y^4}\)=\(\dfrac{5.4xz^2}{3x^2y^4.4xz^2}\)=\(\dfrac{20xz^2}{12x^3y^4z^2}\)

         \(\dfrac{3}{4x^3z^2}\) = \(\dfrac{3.3y^4}{4x^3z^2.3y^4}\)=\(\dfrac{9y^4}{12x^3y^4z^2}\)

\(\dfrac{8}{^{x2+2x-3^{ }}}\)+\(\dfrac{2}{x+3}\)+\(\dfrac{1}{x-1}\)

Giúp mình với nhanh ạ.