\(123-5\left(x+4\right)=38\)

\(\Rightarrow123-5x-20=38\)

\(\Rightarrow-5x=-65\)

\(\Rightarrow x=13\)

Vậy: ...

\(-26\dfrac{5}{6}:\left(-\dfrac{2}{3}\right)+48\dfrac{5}{6}:\left(-\dfrac{2}{3}\right)\)

\(=\left(-26\dfrac{5}{6}+48\dfrac{5}{6}\right):\left(-\dfrac{2}{3}\right)\)

\(=22:\left(-\dfrac{2}{3}\right)\)

\(=-33\)