Câu trả lời:
Câu 6
ad tc của dãy tsbn,ta có:
\(\dfrac{a}{8}\)=\(\dfrac{b}{7}\)=\(\dfrac{c}{6}\)=\(\dfrac{d}{5}\)=\(\dfrac{a+b+c+d}{8+7+6+5}\)=\(\dfrac{234}{26}\)=9
\(\dfrac{a}{8}\)=9=>a=72
\(\dfrac{b}{7}\)=9=>b=63
\(\dfrac{c}{6}\)=9=>c=54
\(\dfrac{d}{5}\)=9=>d=45