Mà mk cx đang cần coin đêy

a hải thiếu dấu câu anh ơi

1. Mai and Mary have been pen pals for over 6 years but this is their first meeting.

2. They are really impressed by the beauty of the city and by the friendliness of its people.

c) \(\left(\dfrac{3}{5}-2x\right)^2+0,4=\dfrac{2}{3}.60\%\)

\(\Rightarrow\) \(\left(\dfrac{3}{5}-2x\right)^2+\dfrac{2}{5}=\dfrac{2}{3}.\dfrac{3}{5}\)

\(\Rightarrow\) \(\left(\dfrac{3}{5}-2x\right)^2=\dfrac{2}{5}-\dfrac{2}{5}=0\)

\(\Rightarrow\) \(\dfrac{3}{5}-2x=0\)

\(\Rightarrow\) \(2x=\dfrac{3}{5}\)

\(\Rightarrow\) \(x=\dfrac{3}{10}\)

Vậy x = \(\dfrac{3}{10}\)

ui mình ghi lôn đừng ghi vô nha

Tham khảo bài mình nhé : Tính A/BA=\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2021}\)B=\(\dfrac{1}{2020}+\dfrac{2}{2019}+\dfrac{3}{20... - Hoc24

Ta có :

B = \(\dfrac{1}{2020}+\dfrac{2}{2019}+\dfrac{3}{2018}+...+\dfrac{2019}{2}+\dfrac{2020}{1}\)

B = \(\left(\dfrac{1}{2020}+1\right)+\left(\dfrac{2}{2019}+1\right)+\left(\dfrac{3}{2018}+1\right)+...+\left(\dfrac{2019}{2}+1\right)+1\)

B = \(\dfrac{2021}{2020}+\dfrac{2021}{2019}+\dfrac{2021}{2018}+...+\dfrac{2021}{2}+1\)

B = \(2021\left(\dfrac{1}{2021}+\dfrac{1}{2020}+\dfrac{1}{2019}+...+\dfrac{1}{2}\right)\)  (1)

Mà A = \(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{2021}\)   (2)

Từ (1) và (2) \(\Rightarrow\) \(\dfrac{A}{B}=\dfrac{1}{2021}\)

You can play football or even go for long walks, but ______ sure it’s three times a week or more.

A.make

B.to make

C.to making

D.making

nhưng mình mới lớp 6 ko trả lời đc nhìu