m ) \(3\dfrac{1}{4}:\left(-\dfrac{4}{5}\right)-2\dfrac{5}{4}.\left(-\dfrac{4}{5}\right)\\ =\left(3\dfrac{1}{4}-2\dfrac{5}{4}\right):\left(-\dfrac{4}{5}.-\dfrac{4}{5}\right)\\ =0:\left(\dfrac{4}{5}\right)\\ =0\)

n ) \(5\dfrac{4}{3}:\left(\dfrac{7}{6}\right)+5\dfrac{1}{3}.\left(-\dfrac{7}{6}\right)\\ =\left(5\dfrac{4}{3}+5\dfrac{1}{3}\right):\left(\dfrac{7}{6}.-\dfrac{7}{6}\right)\\ =\dfrac{35}{3}:1\\ =\dfrac{35}{3}\)

1, aren't playing - are shiping

2, have worked

3, will have

4, opens - closes

fixs `->` fixes

They have moved nothing in your room

- Nothing has been moved in your room.

:")lại một pha viết sai chính tả đi vào lòng đất ạ. Cảm ơn chị đã nhắc

He hates people staring at him.

- He hates being started at.

\(\left(2x+1\right).\left(2x-3\right)-\left(4x+1\right)\left(x+2\right)=8\\ 4x^2-6x+2x-3-4x^2-8x-x-2=8\\ -13x-5=8\\ -13x=13\\ x=-1\)

a. \(4x-5=2\left(x-2\right)-3\\ \Leftrightarrow4x-5=2x-4-3\\ \Leftrightarrow4x-2x=-4+5-3\\ \Leftrightarrow2x=-2\\ x=-1\)

b. Bạn check lại đề nha

c . \(\left|3-2x\right|+7=3x\)

TH1 : \(\left|3-2x\right|=3-2x\) khi \(3-2x\ge0\Leftrightarrow-2x\ge3\Leftrightarrow x\le-\dfrac{3}{2}\)

TH2 : \(\left|3-2x\right|=-3+2x\) khi \(3-2x< 0\Leftrightarrow-2x< 3\Leftrightarrow x>-\dfrac{3}{2}\)

Với \(x\le-\dfrac{3}{2}\) , ta có PT

\(3-2x+7=3x\\ \Leftrightarrow-2x-3x=-7-3\\ \Leftrightarrow-5x=-10\\ \Leftrightarrow x=2\left(loại\right)\)

Với \(x>-\dfrac{3}{2}\) , ta có PT

\(-3+2x+7=3x\\ \Leftrightarrow2x-3x=3-7\\ \Leftrightarrow-x=-4\\ \Leftrightarrow x=4\left(nhận\right)\)

Vậy S = { 4 }

d. \(\left|3x-7\right|-x=0\)

TH1 : \(\left|3x-7\right|=3x-7\) khi \(3x-7\ge0\Leftrightarrow x\ge\dfrac{7}{3}\)

Th2 : \(\left|3x-7\right|=-3x+7\) khi \(3x-7< 0\Leftrightarrow x< \dfrac{7}{3}\)

Với \(x\ge\dfrac{7}{3}\) , ta có PT

\(3x-7-x=0\\ \Leftrightarrow3x-x=0+7\\ \Leftrightarrow2x=7\\\Leftrightarrow x=\dfrac{7}{2}\left(nhận\right)\)

Với \(x< \dfrac{7}{3}\) , ta có PT

\(-3x+7-x=0\\ \Leftrightarrow-3x-x=0-7\\ \Leftrightarrow-4x=-7\\ \Leftrightarrow x=\dfrac{7}{4}\left(nhận\right)\)

Vậy S = { \(\dfrac{7}{2};\dfrac{7}{4}\) }