Kết quả của biểu thức \(A=\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)...\left(1-\dfrac{1}{100}\right)\) là
\(\dfrac{1}{100}\).\(1\).\(\dfrac{1}{50}\).\(\dfrac{99}{100}\).Hướng dẫn giải:\(A=\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)...\left(1-\dfrac{1}{100}\right)\\ =\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot...\cdot\dfrac{98}{99}\cdot\dfrac{99}{100}\\ =\dfrac{1}{100}.\)