Question

x+{(x-3)-[(x+3)-(x-2)]}=0

Answer 1

x+{(x-3)-[(x+3)-(x-2)]}=0

=> x + [x-3-(x+3) + (x-2)] = 0

=> x + (x - 3 - x - 3 + x - 2) = 0

=> x + x - 8 = 0

=> 2x = 8

=> x = 4

Vậy...

Answer 2

x+{(x-3)-[(x+3)-(x-2)]} = 0

=> x + { (x -3) - [ x + 3 - x + 2]} =0

=> x + {(x - 3) - [ 3 + 2 + x - x ]} = 0

=> x + {x - 3 - 5 } = 0

=> x + { x - 8 } = 0

=> x + x - 8 = 0

=> 2x - 8 = 0

2x = 8

x = 4

Answer 3

x+{(x-3)-[(x+3)-(x-2)]} = 0

=> x + { (x -3) - [ x + 3 - x + 2]} =0

=> x + {(x - 3) - [ 3 + 2 + x - x ]} = 0

=> x + {x - 3 - 5 } = 0

=> x + { x - 8 } = 0

=> x + x - 8 = 0

=> 2x - 8 = 0

2x = 8

x = 4