\(\left(x+\dfrac{1}{2}\right).\dfrac{3}{4}=0\)
\(\Leftrightarrow x+\dfrac{1}{2}=0:\dfrac{3}{4}\)
\(\Leftrightarrow x+\dfrac{1}{2}=0\)
\(\Leftrightarrow x=0-\dfrac{1}{2}\)
\(\Leftrightarrow x=\dfrac{-1}{2}\)
Vậy ...
\(\left(x+\dfrac{1}{2}\right).\dfrac{3}{4}=1\)
\(\Rightarrow\left(x+\dfrac{1}{2}\right)=1:\dfrac{3}{4}\)
\(\Rightarrow x+\dfrac{1}{2}=\dfrac{4}{3}\)
\(\Rightarrow x=\dfrac{4}{3}-\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{5}{6}\)