\(\dfrac{x-3}{5}=-\dfrac{1}{2}\)
\(\dfrac{x-3}{5}+\dfrac{1}{2}=0\\ =>2.\left(x-3\right)+5=0\\ =>2x-6+5=0\\ =>2x-1=0\\ =>2x=1\\ =>x=\dfrac{1}{2}\)
do bạn ghi đề ko rõ nên mik làm hai trường hợp lun:
\(x-\dfrac{3}{5}=-\dfrac{1}{2}\\ =>x=-\dfrac{1}{2}+\dfrac{3}{5}\\ =>x=\dfrac{1}{10}\\ =>x=0,1\)