\(x-\dfrac{1}{3}=-\dfrac{2}{5}< =>x=-\dfrac{2}{5}+\dfrac{1}{3}=-\dfrac{1}{15}\)
\(x=\dfrac{-2}{5}+\dfrac{1}{3}=\dfrac{-1}{15}\)
\(x - \dfrac{1}{3} = \dfrac{-2}{5}\)
\(\Rightarrow x = \dfrac{1}{3} + \dfrac{-2}{5} \)
\(\Rightarrow x = \dfrac{5}{15} + \dfrac{6}{16}\)
\(\Rightarrow x = \dfrac{-1}{15}\)
Vậy \(x = \dfrac{-1}{15}\)