\(\dfrac{3}{14}\cdot\left(-49\right)=-\dfrac{21}{2}\)
\(\dfrac{3}{4}\cdot\dfrac{-18}{25}=-\dfrac{27}{50}\)
\(1\dfrac{2}{3}\cdot3\dfrac{2}{9}=\dfrac{29}{9}\cdot\dfrac{5}{3}=\dfrac{145}{27}\)
\(40\%\cdot\dfrac{20}{9}=\dfrac{40}{100}\cdot\dfrac{20}{9}=\dfrac{40}{45}=\dfrac{8}{9}\)
a, \(-49.\dfrac{3}{14}=-\dfrac{21}{2}\)
b, \(\dfrac{-18}{25}.\dfrac{3}{4}=-\dfrac{27}{50}\)
c, \(3\dfrac{2}{9}.1\dfrac{2}{3}=\dfrac{29}{9}.\dfrac{5}{3}=\dfrac{145}{27}\)
d, \(\dfrac{20}{9}.40\%=\dfrac{20}{9}.\dfrac{40}{100}=\dfrac{8}{9}\)