Sửa đề tìm x
\(\frac{-2}{3}-\frac{1}{3}.\left(2x-5\right)=\frac{3}{2}\)
\(\Leftrightarrow\frac{1}{3}\left(2x-5\right)=\frac{-2}{3}-\frac{3}{2}\)\(=\frac{-13}{6}\)
\(\Leftrightarrow\) 2x-5=\(\frac{-13}{6}:\frac{1}{3}=\frac{-13}{6}.3=\frac{-13}{2}\)
\(\Leftrightarrow2x=\frac{-13}{2}+5=\frac{-3}{2}\)
\(\Leftrightarrow x=\frac{-3}{2}:2=\frac{-3}{2}.\frac{1}{2}=\frac{-3}{4}\)
Vậy: x=-3/4