cc,you nói thế thì t cx chẳng muốn làm
để ý thấy: từ: \(100\rightarrow-100\) sẽ có 1 thừa số 0
and........
Ok?
Hmm....
\(\dfrac{100}{1}.\dfrac{99}{2}.\dfrac{98}{3}........\dfrac{-99}{200}.\dfrac{-100}{201}\)
\(=\dfrac{100.99.98..............-99.-100}{1.2.3.....200.201}\)
\(=\dfrac{100.99.98.......0..........-99.-100}{1.2.3....200.201}\)
\(=0\)
1001.992.983...−99200.−1002011001.992.983...−99200.−100201
=100.99.98...−99.−1001.2.3...200.201=100.99.98...−99.−1001.2.3...200.201
=100.99.98...0...−99.−1001.2.3...200.201=100.99.98...0...−99.−1001.2.3...200.201
=0