\(B=\left(4x-3\right)^2+\left(5y-2\right)^2-2016\)
Vì: \(\left(4x-3\right)^2+\left(5y-2\right)^2\ge0\)
=> \(\left(4x-3\right)^2+\left(5y-2\right)^2-2016\ge-2016\)
Dấu "=" xảy ra khi \(x=\frac{3}{4};y=\frac{2}{5}\)
Vậy MinA là -2016 khi \(x=\frac{3}{4};y=\frac{2}{5}\)
A sai đề