Violympic toán 6
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tính
\(G=\left(1-\dfrac{1}{7}\right)\left(1-\dfrac{2}{7}\right)\left(1-\dfrac{3}{7}\right)...\left(1-1\dfrac{2}{7}\right)\left(1-1\dfrac{3}{7}\right)\)
30 tháng 4 2021 lúc 9:24
text{Thực hiện phép tính một cách hợp lý nhất (nếu có thể):}1) left(dfrac{-8}{13}:dfrac{3}{7}+dfrac{-5}{13}:dfrac{3}{7}right).dfrac{left(-4right)^3.left|-3right|}{7}2) 75text{%}-left(dfrac{5}{2}+dfrac{5}{3}right)+left(-dfrac{1}{2}right)^2
Đọc tiếp
\(\text{Thực hiện phép tính một cách hợp lý nhất (nếu có thể):}\)
\(1\)) \(\left(\dfrac{-8}{13}:\dfrac{3}{7}+\dfrac{-5}{13}:\dfrac{3}{7}\right).\dfrac{\left(-4\right)^3.\left|-3\right|}{7}\)
\(2\)) \(75\)\(\text{%}\)\(-\left(\dfrac{5}{2}+\dfrac{5}{3}\right)+\left(-\dfrac{1}{2}\right)^2\)
\(\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)\left(1-\dfrac{1}{5}\right)\left(1-\dfrac{1}{6}\right)\left(1-\dfrac{1}{7}\right)\left(1-\dfrac{1}{8}\right)\left(1-\dfrac{1}{9}\right)\left(1-\dfrac{1}{10}\right)\)
\(A=\left(\dfrac{1}{7}+\dfrac{1}{23}-\dfrac{1}{1009}\right):\left(\dfrac{1}{23}+\dfrac{1}{7}-\dfrac{1}{1009}+\dfrac{1}{7}.\dfrac{1}{23}.\dfrac{1}{1009}\right)+1:\left(30.1009-160\right)\)
tính giá trị biểu thức sau:
\(B=\left(1-\dfrac{1}{7}\right).\left(1-\dfrac{2}{7}\right).\left(1-\dfrac{3}{7}\right)...\left(1-\dfrac{2011}{7}\right)\)
26 tháng 3 2021 lúc 20:29
Tính:
\(A=\)\(\dfrac{1}{5}+\left(\dfrac{-1}{3}+\dfrac{9}{5}\right)+\dfrac{-7}{6}\)
a) \(\dfrac{\left(3+\dfrac{1}{6}\right)-\dfrac{2}{5}}{\left(5-\dfrac{1}{6}\right)+\dfrac{7}{10}}\)
b) \(\dfrac{\left(4,08-\dfrac{2}{25}\right):\dfrac{4}{17}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{7}}\)
c) \(\dfrac{2-\dfrac{1}{4}+\dfrac{1}{3}-\dfrac{3}{5}}{3-\dfrac{1}{5}-\dfrac{5}{3}}\)
Thực hiện phép tính 1 cách hợp lý
\(\dfrac{0,8:\left(\dfrac{4}{5}.1.25\right)}{0,64-\dfrac{1}{25}}+\dfrac{\left(1,08-\dfrac{2}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{17}}\)
a) \(\left(7\dfrac{4}{9}+3\dfrac{7}{11}\right)-3\dfrac{4}{9}\)
b) \(5\dfrac{2}{7}\cdot\dfrac{8}{11}+5\dfrac{2}{7}\cdot\dfrac{5}{11}-5\dfrac{2}{7}\cdot\dfrac{2}{11}\)
c) \(1\dfrac{13}{15}\cdot0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{5}\)
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