Question

tính gía trị của các biểu thức sau :

a, A= 3\(\dfrac{1}{11}\) x \(\dfrac{27}{46}\) x 1\(\dfrac{6}{17}\) x 2\(\dfrac{4}{9}\)

b, B= 2006 x 125 + 1000/126 x 2006 - 1006 .

bạn nào nhanh mk tk nha

Answer 1

a)A=3\(\dfrac{1}{11}\) x \(\dfrac{27}{46}\) x 1\(\dfrac{6}{17}\) x 2\(\dfrac{4}{9}\)

A=\(\dfrac{34}{11}\) x \(\dfrac{27}{46}\) x \(\dfrac{23}{17}\) x \(\dfrac{22}{9}\)

A=\(\dfrac{34\times27\times23\times22}{11\times46\times17\times9}\)

A=\(\dfrac{2\times3}{1}\)

A=6

Answer 2

\(\dfrac{2006\times125+1000}{126\times2006-1006}\)

= \(\dfrac{2006\times125+1000}{125\times2006-2006-1006}\)

=\(\dfrac{2006\times125+1000}{125\times2006+1000}\)

=1