Question

Tính

(\(\frac{1}{\sqrt{625}}\) + \(\frac{1}{5}\) + 1 ) : ( \(\frac{1}{25}\) - \(\frac{1}{\sqrt{25}}\) -1 )

Answer 1

Lớp 6 làm gì học căn bậc . Mình làm cho bạn nếu lớp khác :

\(\left(\frac{1}{\sqrt{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{\sqrt{25}}-1\right)\)

\(=\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)

\(=\frac{31}{25}:\frac{-29}{25}\)

\(=\frac{-31}{29}\)

Answer 2

\(\left(\sqrt[]{\frac{1}{625}}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\sqrt[]{\frac{1}{25}}-1\right)\)

\(\left(\frac{1}{25}+\frac{1}{5}+1\right):\left(\frac{1}{25}-\frac{1}{5}-1\right)\)

\(\frac{31}{25}:\) \(\frac{-29}{25}\) \(=\frac{-31}{29}\)