\(B=\dfrac{2}{7}-\dfrac{6}{7}:3-3:\dfrac{2}{3}\)
\(B=\dfrac{2}{7}-\dfrac{2}{7}-\dfrac{9}{2}=0-\dfrac{9}{2}=-\dfrac{9}{2}\)
Vậy B \(=-\dfrac{9}{2}\)
\(C=1,2.\dfrac{25}{12}-\left(\dfrac{1}{2}+\dfrac{1}{3}\right):-\dfrac{5}{6}\)
\(C=\dfrac{6}{5}.\dfrac{25}{12}-\dfrac{5}{6}.\dfrac{-6}{5}\)
\(C=\dfrac{5}{2}-\left(-1\right)=\dfrac{7}{2}\)
Vậy \(C=\dfrac{7}{2}\)