Question

Tính:

a, 4/12+6/7+8/24

b,9/18+7/12-13/32

Answer 1

a)\(\dfrac{4}{12}+\dfrac{6}{7}\)+\(\dfrac{8}{24}\)=\(\dfrac{32}{21}\)

b)\(\dfrac{9}{18}+\dfrac{7}{12}-\)\(\dfrac{13}{32}\)=\(\dfrac{65}{96}\)

Answer 2

a)\(\dfrac{8}{24}+\dfrac{6}{7}+\dfrac{8}{24}\)

\(\left(\dfrac{8}{24}+\dfrac{8}{24}\right)+\dfrac{6}{7}\)

\(\dfrac{2}{3}+\dfrac{6}{7}\)= \(\dfrac{14}{21}+\dfrac{18}{21}\)

\(\dfrac{32}{21}\)

b)\(\dfrac{65}{96}\)

Answer 3

\(\dfrac{4}{12}+\dfrac{6}{7}+\dfrac{8}{24}=\dfrac{32}{21}\)

\(\dfrac{9}{18}+\dfrac{7}{12}-\dfrac{13}{32}=\dfrac{65}{96}\)