\(a,15\cdot2^3+4\cdot3-5\cdot7\\ =15\cdot8+4\cdot3-5\cdot7\\ =120+12-35\\ =132-35\\ =97\)
\(b,150-\left[10^2-\left(14-11\right)^2\cdot2007^0\right]\\ =150-\left[100-3^2\cdot1\right]\\ =150-\left[100-9\cdot1\right]\\ =150-\left[100-9\right]\\ =150-91\\ =59\)
a) \(15\cdot2^3+4\cdot3-5\cdot7\)
\(=15\cdot8+4\cdot3-5\cdot7\)
\(=120+12-35\)
\(=97\)
b) \(150-\left[10^2-\left(14-11\right)^2\cdot2017^0\right]\)
\(=150-\left[10^2-3^2\cdot2017^0\right]\)
\(=150-\left[100-9\cdot1\right]\)
\(=150-\left[100-9\right]\)
\(=150-91\)
\(=59\)
\(a,15.2^3+4.3-5.7=15.8+12-35=120+12-35=97\)
\(b,150-\left[10^2-\left(14-11\right)^2.2007^0\right]=150-\left(100-3^2.1\right)=150-\left(100-9\right)=150-91=59\)
Chúc bạn học tốt!!!
a) 15. \(2^3\)+ 4 .3 -5 .7
= 15.8 + 4.3 - 5.7
= 120 + 12 - 35
= 97
b) 150 - [ \(10^2\)- (\(14-11^2\)).2007 \(^0\)
= 150 - [100 - 9.1]
= 150 - 91
= 59
