\(\Rightarrow3A=1+\dfrac{1}{3}+...+\dfrac{1}{3^{19}}\)
\(\Rightarrow3A-A=\left(1+\dfrac{1}{3}+...+\dfrac{1}{3^{19}}\right)-\left(\dfrac{1}{3}+\dfrac{1}{3^2}+...+\dfrac{1}{3^{20}}\right)\)
\(\Rightarrow2A=1-\dfrac{1}{3^{20}}\)
\(\Rightarrow A=\dfrac{1-\dfrac{1}{3^{20}}}{2}\)