Đặt A = 4 + 12 + 24 + ... + 19404 + 19800
\(\dfrac{1}{2}\) A = 2 + 6 + 12 + ... + 9702 + 9900
\(\dfrac{1}{2}\) A = 1.2 + 2.3 + 3.4 + ... + 98.99 + 99.100
\(\dfrac{3}{2}A\) = 1.2.3 + 2.3.(4-1) + 3.4.(5-2) + ... + 98.99.(100-97) + 99.100.(101-98)
\(\dfrac{3}{2}A\) = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + ... + 99.100.101 - 98.99.100
A =(99.100.101).\(\dfrac{2}{3}\)
A = 666600