Question

Tính:

1) ( \(5\dfrac{7}{9}\)+2\(\dfrac{3}{11}\)) - ( -1\(\dfrac{8}{11}\) + 3\(\dfrac{7}{9}\))

2) ( 2\(\dfrac{7}{19}\) - 3\(\dfrac{8}{9}\) ) - ( 1\(\dfrac{7}{19}\) - 2\(\dfrac{1}{9}\))

Giúp mình nhé mình đang cần gấp

Answer 1

câu a

\(\left(5\dfrac{7}{9}+2\dfrac{3}{11}\right)-\left(-1\dfrac{8}{11}+3\dfrac{7}{9}\right)\)

= \(5\dfrac{7}{9}+2\dfrac{3}{11}+1\dfrac{8}{11}-3\dfrac{7}{9}\)

= \(\left(5\dfrac{7}{9}-3\dfrac{7}{9}\right)+\left(2\dfrac{3}{11}+1\dfrac{8}{11}\right)\)

= \(2+3\dfrac{11}{11}\)

= \(2+3+1\)

= \(6\)

Answer 2

câu b

\(\left(2\dfrac{7}{19}-3\dfrac{8}{9}\right)-\left(1\dfrac{7}{19}-2\dfrac{1}{9}\right)\)

= \(2\dfrac{7}{19}-3\dfrac{8}{9}-1\dfrac{7}{19}+2\dfrac{1}{9}\)

= \(\left(2\dfrac{7}{19}-1\dfrac{7}{19}\right)-\left(3\dfrac{8}{9}-2\dfrac{1}{9}\right)\)

= \(1-1\dfrac{7}{9}\)

= \(\dfrac{-7}{9}\)