1+\(\frac{5}{3.5}+\frac{5}{5.7}+\frac{5}{7.9}+...+\frac{5}{97.99}\)
=1+\(\frac{5}{2}.(\frac{1}{3}-\frac{1}{5})+\frac{5}{2}.(\frac{1}{5}-\frac{1}{7})+\frac{5}{2}.(\frac{1}{7}-\frac{1}{9})\)+...+\(\frac{5}{2}.(\frac{1}{97}-\frac{1}{99})\)
=1+\(\frac{5}{2}.(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{97}-\frac{1}{99})\)
=1+\(\frac{5}{2}.(\frac{1}{3}-\frac{1}{99})\)
=1+\(\frac{5}{2}.\frac{32}{99}\)
=1+\(\frac{80}{99}\)
=\(\frac{179}{99}\)