\(y:\dfrac{2}{3}=\dfrac{1}{3}+\dfrac{2}{3}\)
\(y:\dfrac{2}{3}=\dfrac{3}{3}=1\)
\(y=1\times\dfrac{2}{3}=\dfrac{2}{3}\)
Ta có: \(y:\dfrac{2}{3}=\dfrac{1}{3}+\dfrac{2}{3}\)
\(\Leftrightarrow y:\dfrac{2}{3}=1\)
\(\Leftrightarrow y=\dfrac{2}{3}\)
Vậy: \(y=\dfrac{2}{3}\)