Question

Tìm \(x\in Z\) biết :

\(-10\le\)/5-x/\(\le\)2

Answer 1

\(-10\le\left|5-x\right|\le2\)

\(\Rightarrow\left|5-x\right|=1;2\)

\(\Rightarrow5-x=\pm1\) hoặc \(5-x=\pm2\)

+) \(5-x=1\Rightarrow x=4\)

+) \(5-x=-1\Rightarrow x=6\)

+) \(5-x=2\Rightarrow x=3\)

+) \(5-x=-2\Rightarrow x=7\)

Vậy \(x\in\left\{4;6;3;7\right\}\)

 

Answer 2

\(-10\le\left|5-x\right|\le2\\ \Rightarrow\left|5-x\right|=1;2\\ \Rightarrow5-x=\pm1ho\text{ặ}c5-x=\pm2\\ \)

+) \(5-x=1\\ \Rightarrow x=4\\ \)

+) \(5-x=-1\Rightarrow x=6\)

+) \(5-x=2\Rightarrow x=3\)

+) \(5-x=-2\Rightarrow x=7\\ \)

Vậy \(x\in\left\{4;6;3;7\right\}\)