\(x^2-2x=0\)
\(\Leftrightarrow x.\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=0+2=2\end{matrix}\right.\)
Vậy : \(x\in\left\{0,2\right\}\)
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x\(^2\)−2x=0
=>x.(x−2)=0
=>\(\left[{}\begin{matrix}x=0\\x-2=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=0\\x=2\end{matrix}\right.\)
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