Question

Tìm x:

b) \(\frac{2}{9}\) + \(\frac{7}{8}\) nhân x = \(\frac{1}{3}\)      c) \(\frac{4}{5}\) + \(\frac{5}{7}\) : x = \(\frac{1}{3}\)

Answer 1

b) \(\frac{2}{9}+\frac{7}{8}.x=\frac{1}{3}\)

\(\frac{1}{3}-\frac{2}{9}=\frac{7}{8}.x\)

\(\frac{7}{8}.x=\frac{1}{9}\)

\(x=\frac{1}{9}:\frac{7}{8}\)

\(x=\frac{8}{63}\)

c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)

\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}\)

\(\frac{5}{7}:x=\frac{-7}{15}\)

\(x=\frac{5}{7}:\frac{-7}{15}\)

\(x=\frac{75}{-49}\)

Answer 2

b) \(\frac{2}{9}+\frac{7}{8}x=\frac{1}{3}\)

\(\frac{7}{8}x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

\(x=\frac{1}{9}:\frac{7}{8}=\frac{8}{63}\)

c) \(\frac{4}{5}+\frac{5}{7}:x=\frac{1}{3}\)

\(\frac{5}{7}:x=\frac{1}{3}-\frac{4}{5}=-\frac{7}{15}\)

\(x=\frac{5}{7}:\left(-\frac{7}{15}\right)=-\frac{75}{49}\)

Answer 3

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