Question

tìm x

5^x+5^x+1+5^x+2=31

Answer 1

5^x + 5^(x + 1) + 5^(x + 2) = 31

5^x.(1 + 5 + 5²) = 31

5^x . 31 = 31

5^x = 31 : 31

5^x = 1

5^x = 5⁰

x = 0

Answer 2

\(5^x+5^x.5^1+5^x.5^2=31\)

\(5^x+5^x.5+5^x.25=31\)

\(5^x.\left(25+5+1\right)=31\)

\(5^x.31=31\)

\(5^x=31\div31\)

\(5^x=1\)

\(x=0\)

Answer 3

5^x+5^x+1+5^x+2=31

5^x.(1+5+5²)=31

5^x.31=31

5^x=31:31

5^x=1

5^x=5⁰

x=0

Vậy x=0

Answer 4

\(5^x+5^x\cdot5+5^x\cdot5^2=31< =>5^x\left(1+5+5^2\right)=31< =>5^x\cdot31=31< =>5^x=1< =>x=0\)