\(\left(x+4\right).11=x.14\\ \Leftrightarrow11x+44=14x\\ \Leftrightarrow11x-14x=-44\\ \Leftrightarrow-3x=-44\\ \Leftrightarrow x=\dfrac{44}{3}\)
Vậy \(x=\dfrac{44}{3}\)
\(\left(x+4\right).11=x.14\)
\(11x+44-14x=0\)
\(-3x-44=0\)
\(-3x=44\)
\(x=\dfrac{44}{3}\)
(x + 4).11 = x.14
11.(x + 4) = 14x
11x = 14x - 44
11x - 14x = 14x - 44 + 14x
-3x = -44
x = 44/3
Ta có: (x+4).11=x.14
\(\Leftrightarrow11x+44=14x\)
\(\Leftrightarrow44=14x-11x\)
\(\Leftrightarrow44=3x\)
\(\Leftrightarrow x=\dfrac{44}{3}\)
Vậy:............
