Ta có :
\(x\div\dfrac{41}{3}=-2,5\)
\(\Leftrightarrow x=\left(-2,5\right)\times\dfrac{41}{3}\)
\(\Leftrightarrow x=-\dfrac{205}{6}\)
Vậy \(x=-\dfrac{205}{6}\)
\(x:4\dfrac{1}{3}=-2,5\)
\(\Rightarrow x:\dfrac{13}{3}=\dfrac{-25}{10}\)
\(\Rightarrow x=\dfrac{-25}{10}.\dfrac{13}{3}\)
\(\Rightarrow x=\dfrac{-65}{6}\)