Question

Tìm x

x.[(1800+600):30]=560:(315:15)

Answer 1

\(x.[(1800+600):30]=560:(315:15)\)

\(\Leftrightarrow x.\dfrac{1800+600}{30}=560:\dfrac{315}{15}\)

\(\Leftrightarrow x.80=\dfrac{80}{3}\)

\(\Leftrightarrow x=\dfrac{80}{3}:80\)

\(\Leftrightarrow x=\dfrac{1}{3}\)

Vậy \(x=\dfrac{1}{3}\)

Answer 2

\(x.\left[\left(1800+600\right):30\right]=560:\left(315:15\right)\)

\(x.\left[2400:30\right]=560:21\)

\(x.80=\dfrac{80}{3}\)

\(x=\dfrac{80}{3}:80\)

\(x=\dfrac{1}{3}\)