(x - 6)3 = (x - 6)2
Th1:
x - 6 = 1
x = 1 + 6
x = 7
Th2:
x - 6 = 0
x = 6
Vậy x = 7 hoặc x = 6
\(\left(x-6\right)^3=\left(x-6\right)^2\)
\(\Leftrightarrow\left(x-6\right)^3-\left(x-6\right)^2=0\)
\(\Leftrightarrow\left(x-6\right)^2.\left[\left(x-6\right)-1\right]=0\)
\(\Leftrightarrow\left(x-6\right)^2.\left(x-7\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x-6=0\\x-7=0\end{array}\right.\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=6\\x=7\end{array}\right.\)
Vậy \(x=6;7\)