Question

tìm x

x-4=11-2x

(x-3).(x-2)=0

7x-10=x-28

\(\left|x-5\right|=10-\left|-2\right|\)

Answer 1

ko biết

Answer 2

1.

\(x-4=11-2x\)

\(\Leftrightarrow x+2x=11+4\)

\(\Leftrightarrow 3x=15\Leftrightarrow x=15:3=5\)

2.

\((x-3)(x-2)=0\Rightarrow \left[\begin{matrix} x-3=0\\ x-2=0\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=3\\ x=2\end{matrix}\right.\)

Answer 3

3.

\(7x-10=x-28\)

\(\Leftrightarrow 7x-10-(x-28)=0\)

\(\Leftrightarrow 6x+18=0\Leftrightarrow 6x=-18\Leftrightarrow x=-3\)

4.

\(|x-5|=10-|-2|=10-2=8\)

\(\Rightarrow \left[\begin{matrix} x-5=8\\ x-5=-8\end{matrix}\right.\Rightarrow \left[\begin{matrix} x=13\\ x=-3\end{matrix}\right.\)