Question

Tìm x thuộc Z ,biết: a) 3x(x+1) - 6(x+1) = 0 ; b) (2x+25) - 2(10-3x) = 0 ; c)|x-3| = 7-(-2)

Answer 1

a)

\(3x\left(x+1\right)-6\left(x+1\right)=0\\ \Leftrightarrow\left(x+1\right)\left(3x-6\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

b)

\(2x+25-2\left(10-3x\right)=0\\ \Leftrightarrow8x+5=0\\ \Leftrightarrow x=-\dfrac{5}{8}\)

c)

\(\left|x-3\right|=7-\left(-2\right)\\ \Rightarrow\left|x-3\right|=9\\ \Rightarrow\left[{}\begin{matrix}x=12\\x=-6\end{matrix}\right.\)