Question

Tìm x thuộc N

x + ( x + 1 ) + (x + 2 ) +......+( x + 30 ) = 1240

1+2+3+......+x = 210

Tìm x,y thuộc N

( x +1 ) . ( 2y -5 ) = 143

Answer 1

x + ( x + 1 ) + ( x + 2 )+.........+ (x + 30)= 1240

x + ( x . 30 ) + ( 1 + 2 + .... + 30 ) = 1240

x . 31 + ( 1 + 2 + .... + 30 ) = 1240

x.31 +[( 31-1)+1] = 1240

x.31 + [( 30+1)*30:2] = 1240

x.31 + 465 = 1240

x.31 = 1240 - 465

x.31 = 775

x = 775 : 31

x = 25

Answer 2

1+2+3+...+x=210

(x+1).x:2=210

(x+1).x=210.2

(x+1).x=420

(x+1).x=(20+1).20

=>x=20

Answer 3

x+x+x+...+x+(1+2+...+30)=1240

31.x+(1+2+...+30)=1240

31.x+465=1240

31.x=1240-465

31.x=775

x=775:31

x=25