x-1/9 = 8/3
=> (x-1).3 = 9.8
=> (x-1).3 = 72
x-1 = 72:3
x-1 = 24
x = 24+1
=> x = 25
\(\frac{x-1}{9}=\frac{8}{3}\Rightarrow\frac{x-1}{9}=\frac{24}{9}\)\(\Leftrightarrow x-1=24\Rightarrow x=24+1=25\)
Vậy x=25
\(\frac{x-1}{9}=\frac{8}{3}\)<=> \(\frac{x-1}{9}=\frac{24}{9}\)=> x-1=24=>x=24+1=25
\(\frac{x-1}{9}=\frac{8}{3}\)
ta có : \(\left(x-1\right).3=9.8\)
\(3x-3=72\)
\(3x=72+3\)
\(3x=75\)
\(x=\frac{75}{3}\)
Để \(\frac{x-1}{9}=\frac{8}{3}\)
<=> ( x - 1 ) . 3 = 8 . 9
=> ( x - 1 ) . 3 = 72
=> x - 1 = 72 : 3
=> x - 1 = 24
=> x = 24 + 1
=> x = 25
Vậy x = 25
x-1=8 9 3
x-1=24 9 9
→x-1=24→x=24+1→x=25
Vậy x =25
\(\frac{x-1}{9}=\frac{8}{3}\)
\(\Rightarrow\left(x-1\right).3=9.8\)
\(\left(x-1\right).3=72\)
\(x-1=72:3\)
\(x-1=24\)
\(x=24+1\)
\(x=25\)
Vậy x = 25
cảm ơn mọi người nhìu!!!!!!!!!!!1