Question

Tìm x \(\in\) N

x : (9\(\dfrac{1}{2}\) - \(\dfrac{3}{2}\)) = \(\dfrac{0,4+\dfrac{2}{9}-\dfrac{2}{11}}{1,6+\dfrac{8}{9}-\dfrac{8}{11}}\)

Answer 1

\(x\div\left(9\dfrac{1}{2}-\dfrac{3}{2}\right)=\dfrac{0,4+\dfrac{2}{9}-\dfrac{2}{11}}{1,6+\dfrac{8}{9}-\dfrac{8}{11}}\)

\(x\div\left(\dfrac{19}{2}-\dfrac{3}{2}\right)=\dfrac{\dfrac{28}{45}-\dfrac{2}{11}}{\dfrac{112}{45}-\dfrac{8}{11}}\)

\(x\div8=\dfrac{\dfrac{218}{495}}{\dfrac{872}{495}}\)

\(\Rightarrow x\div8=\dfrac{218}{495}\div\dfrac{872}{495}\)

\(x\div8=\dfrac{1}{4}\)

\(x=\dfrac{1}{4}\times8\)

\(x=2\)

Vậy \(x=2\)