Question

Tìm x :

\(\frac{x-1}{2009}+\frac{x-2}{2008}+\frac{x-3}{2007}+\frac{x-4}{2006}\)

Giúp mk vs   , cảm ơn nhiều   

Answer 1

Thiếu đề

hik như x=2010

Answer 2

Ta có :

(x+1)/2009 + (x+2)/2008 = (x+3)/2007 + (x+4)/2006
<=> (x+1)/2009 + 1 + (x+2)/2008 + 1 = (x+3)/2007 +1 + (x+4)/2006 + 1
<=> (x+2010)/2009 + (x+2010)/2008 = (x+2010)/2007 + (x+2010)/2006
<=> (x + 2010).[ 1/2009 + 1/2008 - 1/2007 - 1/2006 ] = 0
<=> x = -2010