Ta có: \(2.\left|x-1\right|^2-3=5\)
\(\Rightarrow2.\left|x-1\right|^2=3+5=8\)
\(\Rightarrow\left|x-1\right|^2=8:2=4=2^2\)
\(\Rightarrow\left|x-1\right|=2\)
\(\Rightarrow\left[\begin{array}{nghiempt}x-1=2\\x-1=-2\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x=3\\x=-1\end{array}\right.\)
Vậy: \(x=-1;3\)
Sakura Linh Chúc bạn hok tốt