\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=6^x\)
\(\Rightarrow\dfrac{11.3^{29}-3^{30}}{2^2.3^{28}}=6^x\)
\(\Leftrightarrow\dfrac{3^{29}\left(11-3\right)}{2^2.3^{28}}=6^x\)
\(\Leftrightarrow\dfrac{3.8}{4}=6^x\)
\(\Leftrightarrow6^1=6^x\)
\(\Leftrightarrow x=1\)
Vậy..