Tìm x bt :
a) x + x - 1 + x - 2 +...+z - 50 = 255
b) \(\left(x-\dfrac{1}{3}\right)^2-\dfrac{1}{4}=0\)
c) -2x + 624 = 5y (x,y \(\in\) N )
d) \(\dfrac{x+5}{2}=\dfrac{8}{x+5}\)
e) x + ( x + 1 ) + ( x + 2 ) +...+ ( x + 30 ) =1240
f) ( x - 1 ) + ( x - 2 ) + ... + (x - 19 ) + ( x - 20 ) = -610
g) ( 7x - 11 )3 = ( -3 )2 . 15 + 208
a)
\(x+\left(x-1\right)+\left(x-2\right)+...+\left(x-50\right)=255\\ x+x-1+x-2+...+x-50=255\\ \left(x+x+x+...+x\right)-\left(1+2+3+...+50\right)\\ 51x-1275=255\\ 51x=1530\\ x=30\)
e)
\(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\\ x+x+1+x+2+...+x+30=1240\\ \left(x+x+x+...+x\right)+\left(1+2+3+...+30\right)=1240\\ 31x+465=1240\\ 31x=775\\ x=25\)
f)
\(\left(x-1\right)+\left(x-2\right)+...+\left(x-19\right)+\left(x-20\right)=-610\\ x-1+x-2+...+x-19+x-20=-610\\ \left(x+x+x+...+x\right)-\left(1+2+3+...+20\right)=-610\\ 20x-210=-610\\ 20x=-400\\ x=-20\)
