\(\frac{3+x}{7+x}=\frac{1}{3}\left(ĐK:x\ne-7\right)\)
\(\Leftrightarrow3\left(3+x\right)=7+x\)
\(\Leftrightarrow9+3x=7+x\)
\(\Leftrightarrow2x=-2\)
\(\Leftrightarrow x=-1\)
tìm x biết
\(\frac{3+x}{7+x}=\frac{1}{3}\)
Tìm x biết
a) x + \(2\frac{3}{4}=5\frac{2}{3}\)
b)X x \(3\frac{1}{2}=4\frac{3}{4}\)
c) x - \(4\frac{1}{5}=3\frac{2}{7}\)
d) x - \(\frac{3}{4}=6\text{x}\frac{3}{8}\)
e) \(\frac{7}{8}:x=3\frac{1}{2}\)
tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
tìm x biết :
a) \(\frac{6}{7}.x=\frac{18}{23}\)
b) \(2\frac{1}{2}.x=\frac{5}{6}\)
c) \(x:2\frac{3}{4}=9\frac{5}{8}\)
d)\(7\frac{1}{7}.\frac{1}{7}.x=22\frac{1}{8}\)
Tìm x biết:
25%x + x - \(\frac{1}{5}\)x = \(\frac{1}{5}\)\(\frac{2}{3}\)x - \(\frac{1}{2}\)x = \(\frac{3}{5}\)\(\frac{2}{5}\)x - \(1\frac{1}{2}\)x + x =\(\frac{1}{3}\)\(\left(x+\frac{2}{7}\right).\left(\frac{2}{3}-2x\right)=0\)Cho biểu thức:\(A=\left(9\frac{3}{4}:5,2+x.2\frac{7}{24}\right):1\frac{9}{16}\)
Tìm x biết A=6
Tìm x, biết \(\frac{x}{5}\)+\(\frac{7}{3}\)=\(\frac{10}{3}\)
tìm số x , biết :
a) \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
c) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
d) \(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
e) \(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
f) \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)
