\(x+\frac{x}{3}=24\)
\(\Rightarrow\frac{3x}{3}+\frac{x}{3}=24\)
\(\Rightarrow\frac{4x}{3}=24\)
\(\Rightarrow4x=72\)
\(\Rightarrow x=18\)
Vậy \(x=18\)
\(x+\frac{x}{3}=24\)
\(\Leftrightarrow\frac{2x}{3}=24\)
\(\Leftrightarrow2x=8\)
\(\Leftrightarrow x=4\)