Question

Tìm x , biết :

\(\frac{73-x}{98-x}=\frac{1}{6}\)

Answer 1

Ta có: \(\frac{73-x}{98-x}=\frac{1}{6}\)

\(\Rightarrow6\left(73-x\right)=98-x\)

\(\Rightarrow438-6x=98-x\)

\(\Rightarrow438-98=-x+6x\)

\(\Rightarrow340=5x\)

\(\Rightarrow x=340:5=68\)

Answer 2

\(\frac{73-x}{98-x}=\frac{1}{6}\)

=> \(6\left(73-x\right)=98-x\)

=> \(438-6x=98-x\)

\(\Leftrightarrow-6x+x=98-438\)

\(\Leftrightarrow-5x=-340\)

\(\Leftrightarrow x=68\)

Answer 3

Giải:

Ta có: \(\frac{73-x}{98-x}=\frac{1}{6}\)

\(\Rightarrow\left(73-x\right)6=98-x\)

\(\Rightarrow438-6x=98-x\)

\(\Rightarrow6x-x=438-98\)

\(\Rightarrow5x=340\)

\(\Rightarrow x=68\)

Vậy \(x=68\)