\(60\%x=\dfrac{1}{3}.6\dfrac{1}{3}\\ \dfrac{3}{5}x=\dfrac{1}{3}.\dfrac{19}{3}\\ \dfrac{3}{5}x=\dfrac{19}{9}\\ x=\dfrac{19}{9}:\dfrac{3}{5}\\ x=\dfrac{19}{9}.\dfrac{5}{3}\\ x=\dfrac{95}{27}\)
\(\dfrac{-2}{3}.x+\dfrac{1}{5}=\dfrac{3}{10}\\ \dfrac{-2}{3}.x=\dfrac{3}{10}-\dfrac{1}{5}\\ \dfrac{-2}{3}.x=\dfrac{3}{10}-\dfrac{2}{10}\\ \dfrac{-2}{3}.x=\dfrac{1}{10}\\ x=\dfrac{1}{10}:\dfrac{-2}{3}\\ x=\dfrac{1}{10}.\dfrac{-3}{2}\\ x=\dfrac{-3}{20}\)
a, \(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\)
\(\Rightarrow\dfrac{2}{3}:x=-7-\dfrac{1}{3}\)
\(\Rightarrow\dfrac{2}{3}:x=-\dfrac{22}{3}\)
\(\Rightarrow x=\dfrac{2}{3}:\dfrac{-22}{3}\)
\(\Rightarrow x=-\dfrac{1}{11}\)
b, \(60\%x=\dfrac{1}{3}.6\dfrac{1}{3}\)
\(\Rightarrow\dfrac{3}{5}x=\dfrac{19}{9}\)
\(\Rightarrow x=\dfrac{19}{9}:\dfrac{3}{5}\)
\(\Rightarrow x=\dfrac{95}{27}\)
c, \(-\dfrac{2}{3}x+\dfrac{1}{5}=\dfrac{3}{10}\)
\(\Rightarrow\dfrac{-2}{3}x=\dfrac{3}{10}=\dfrac{1}{5}\)
\(\Rightarrow\dfrac{-2}{3}x=\dfrac{1}{10}\)
\(\Rightarrow x=\dfrac{1}{10}:\dfrac{-2}{3}\)
\(\Rightarrow x=\dfrac{-3}{20}\)
d, \(\left|3x-1\right|=\left(-\dfrac{1^2}{3}\right)\)
\(\left|3x-1\right|=\dfrac{-1}{3}\)
Không tìm được giá trị của x thỏa mãn.
\(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\\ \dfrac{2}{3}:x=-7-\dfrac{1}{3}\\ \dfrac{2}{3}:x=\dfrac{-21}{3}-\dfrac{1}{3}\\ \dfrac{2}{3}:x=\dfrac{-22}{3}\\ =x=\dfrac{2}{3}:\dfrac{-22}{3}\\ x=\dfrac{2}{3}.\dfrac{-3}{22}\\ x=\dfrac{-1}{11}\)
\(\left|3x-1\right|=\left(-\dfrac{1^2}{3}\right)\\ \left|3x-1\right|=-\dfrac{1}{3}\\ \)
Vậy không tìm được x vì giá trị tuyệt đối không có giá trị là âm
