a) 11(x-6)= 4x+11
<=> 11x-66= 4x+11
<=>11x-4x= 11+66
<=> 7x= 77
=>x=11
Vậy: x=11
b) \(4\dfrac{1}{3}\left(\dfrac{1}{6}-\dfrac{1}{2}\right)=\dfrac{13}{3}.\dfrac{-1}{3}=-\dfrac{13}{9}=-1\dfrac{4}{9}\)
\(\dfrac{2}{3}\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{3}{4}\right)=\dfrac{2}{3}.\dfrac{-7}{12}=-\dfrac{7}{18}\)
Vậy: x= -1
BT3: Tìm x, biết:
7) \(\dfrac{-5}{17}+\dfrac{3}{17}\le\dfrac{x}{17}\le\dfrac{13}{17}+\dfrac{-11}{17}\)
8) \(\dfrac{2}{3}\left(\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{3}\right)\le\dfrac{x}{18}\le\dfrac{7}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\)
a)x=\(\dfrac{1}{4}+\dfrac{2}{13}\)
b)\(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
c)\(\dfrac{-8}{3}+\dfrac{-1}{3}\le x\le\dfrac{-2}{7}+\dfrac{-5}{7}\)
d)\(\dfrac{-5}{6}+\dfrac{8}{3}\dfrac{29}{-x}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
Rút gọn
a) B=(\(1-\dfrac{1}{2}\))x\(\left(1-\dfrac{1}{3}\right)x\left(1-\dfrac{1}{4}\right)x....\left(1-\dfrac{1}{20}\right)\)
b) tính nhanh
P=\(\dfrac{\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}}{\dfrac{5}{12}+1-\dfrac{6}{11}}\)
bài 1 : tính
a,\(\dfrac{-6}{11}\): (\(\dfrac{3}{5}.\)\(\dfrac{4}{11}\))
b, \(\dfrac{7}{12}\) + \(\dfrac{5}{12}\) : 6 - \(\dfrac{11}{36}\)
c, ( \(\dfrac{4}{5}\) +\(\dfrac{1}{2}\) ) : ( \(\dfrac{3}{13}\)-\(\dfrac{8}{13}\))
d, ( \(\dfrac{2}{3}\) -\(\dfrac{1}{4}\) +\(\dfrac{5}{11}\) ) : ( \(\dfrac{8}{12}\) +1 - \(\dfrac{7}{11}\) )
bài 2 , tìm x, biết
a, \(\dfrac{-2}{5}\). x +\(\dfrac{4}{3}\) = \(\dfrac{7}{3}\)
b,\(\dfrac{9}{8}\)+\(\dfrac{3}{8}\)-x = 0,125
c,\(\dfrac{3}{4}\): x =\(\dfrac{-7}{12}\)
d,\(\dfrac{3}{8}\)-\(\dfrac{1}{6}\)- x = \(\dfrac{1}{4}\)
e, \(\dfrac{1}{3}\)+\(\dfrac{1}{2}\): x = -4
Tìm x \(\in\) Z :
a \(\left(\dfrac{3}{4}\right)^{2x}=\dfrac{12.5^9.\left(-7\right)^{10}+3.7^9.\left(-5\right)^{11}}{35^9.2^4}\)
b, \(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{10}+....+\dfrac{2}{x\left(x+1\right)}=\dfrac{499}{1000}\)
NHANH NHÁ GIÚP MINK VỚI GIẢI RÕ CHI TIẾT MAI MIK NỘP RỒI ! THANKS TRC^^
Tìm x, y \(\in Z\) thỏa mãn:
a. \(\dfrac{x}{3}-\dfrac{1}{y}=\dfrac{1}{2}\)
b. \(\dfrac{4}{x}+\dfrac{y}{3}=\dfrac{1}{6}\)
c.\(\dfrac{5}{x}-\dfrac{1}{6}=\dfrac{y}{3}\)
tính:
\(\dfrac{2}{5}x\dfrac{1}{3}-\dfrac{2}{15}:\dfrac{1}{5}+\dfrac{3}{5}x\dfrac{1}{3}\)
2)\(\left(3\dfrac{1}{3}+2,5\right):\left(3\dfrac{1}{6}-4\dfrac{1}{5}\right)-\dfrac{11}{31}\)
3)\(\left[6+\left(\dfrac{1}{2^{ }}\right)^3-\left|-\dfrac{1}{2}\right|\right]:\dfrac{3}{12}\)
4)\(\dfrac{18}{37}+\dfrac{8}{24}+\dfrac{19}{37}-1\dfrac{23}{24}+\dfrac{2}{3}\)
5) \(\left(-2\right)^3x\left(\dfrac{3}{4}-0,25\right):\left(2\dfrac{1}{4}-1\dfrac{1}{6}\right)\)
6)\(\left(\dfrac{2}{5}\right)^2+5\dfrac{1}{2}x\left(45-2\right)+\dfrac{23}{-4}\)
7)\(\dfrac{4}{9}-19\dfrac{1}{3}-\dfrac{4}{9}x39\dfrac{1}{3}\)
8)\(\left(-\dfrac{1}{2}\right)^2:\dfrac{1}{4}-2x\left(-\dfrac{1}{2}\right)^2\)
9)\(125\%x\left(-\dfrac{1}{2}\right)^3:\left(1\dfrac{5}{16}-1,5\right)+2008^0\)
giúp mình nha mai mình học rùi 
Bài 1 : Tìm GTNN
A = \(\left(x-\dfrac{1}{4}\right)^2+\left|y+\dfrac{1}{4}\right|+\dfrac{13}{14}\)
Bài 2 : Tìm x , y là số nguyên
a) \(\dfrac{x+3}{5}-\dfrac{1}{y-1}=\dfrac{2}{5}\)
b) \(-1-\dfrac{7}{14}\le\dfrac{x}{3}\le1+\dfrac{12}{48}\)
c) \(\dfrac{2y+7}{y-2}\in Z\)
giúp mk với sáng mai mk có tiết toán
Bài 1: Thực hiện phép tính (hợp lý nếu có thể)
\((6\dfrac{4}{9}+3\dfrac{7}{11})-4\dfrac{4}{9}\)
\(1\dfrac{1}{3}-2\dfrac{5}{6}-\dfrac{6}{11}+3:5\%\)
\(4\dfrac{3}{4}-0,37+\dfrac{1}{8}-1,28-2,5+3\dfrac{1}{12}\)
\(\dfrac{5}{7}.\dfrac{5}{11}+\dfrac{5}{7}.\dfrac{2}{11}-\dfrac{5}{7}.\dfrac{14}{11}\)
\(\dfrac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7^2\right)^2}\)
